Respuesta :

Answer:

A. 3(t+2)

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The result is

A. 3(t+2)

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[tex]\bf \cfrac{~~\frac{4t^2-16}{8}~~}{\frac{t-2}{6}}\implies \cfrac{4(t^2-4)}{8}\cdot\cfrac{6}{t-2}\implies \cfrac{4\stackrel{\stackrel{difference}{of~squares}}{(t^2-2^2)}}{\underset{4}{~~\begin{matrix} 8 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}\cdot\cfrac{\stackrel{3}{\begin{matrix} 6 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}}~~}{t-2}[/tex]

[tex]\bf \cfrac{\begin{matrix} 4 (t-2) \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~(t+2)}{~~\begin{matrix} 4 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}\cdot \cfrac{3}{~~\begin{matrix} t-2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}\implies 3(t+2)[/tex]

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