Question

3. 200 ml of 0.2 M HCl is neutralized with 0.1 M
NaOH. Then during their half neutralization,
what will be the molarity of HCI?

a. 0.1 M
b. 0.5 M
C. 0.05 M
d. 1 M​

Answer 1

Answer:

• a. 0.1 M

Explanation:

By definition, half neutralization is the point at which half of the acid has been neutralized.

The neutralization reaction that you are studying is the acid-base reaction:

• HCl (aq) + NaOH (aq) → NaCl(aq) + H₂O (aq)

Then, since the starting molarity of the acid (HCl) is 0.2 M, you just need to find half of that concentration:

• Half molarity = M / 2 = 0.2 M / 2 = 0.1 M

So, the answer is the first choice: a. 0.1 M.