Question

What is the solution to this Logarithmic Equation?
(Those are L's infront of the N)
ln x + ln x = 0

Answer 1

Answer:

x = 1

Step-by-step explanation:

ln x + ln x = 0

2ln x = 0

ln x = 0

recall ln x = $log_{e}$x

so equation becomes

$log_{e}$x = 0

or $e^{0}$=x

since anything raised to the power of zero = 1

x = 1

Answer 2

Answer:

x = 1

Step-by-step explanation:

We are to find the solution of the following logarithmic equation:

$ln ( x ) + l n ( x ) = 0$

We will add the similar elements to get:

$2 l n ( x ) = 0$

Dividing both sides by 2 and simplify to get:

$\frac { 2 l n ( x ) } { 2 } = \frac { 0 } { 2 }$

$ln(x)=0$

Applying the rule $a=log_b(b^a)$ to get:

$0=ln(e^0)=ln(1)$

$ln(x)=ln(1)$

Here the logs have the same base, so:

x = 1