Answer:
(A). The magnitude and direction of the boat's velocity with respect to the ground is 2 km/h in positive x-axis.
(B). The magnitude and direction of the child’s velocity with respect to the ground is 2 km/h in negative x-axis.
Explanation:
Given that,
The velocity of the boat [tex]v_{bw}= 10\ km/h[/tex]
The velocity of the water[tex]v_{wG} = 8.0\ km/h[/tex]
(a). We need to calculate the magnitude of the boat's velocity with respect to the ground.
The equation for the the boat's velocity with respect to the ground
[tex]v_{bG}=v_{bw}-v_{wG}[/tex]
[tex]v_{bG}=10-8=2\ km/h[/tex]
(b). The direction of the boat's velocity with respect to the ground is in positive x axis.
(c). The velocity of the child with respect to the boat
[tex]v_{cb}=4.0\ km/h[/tex]
The magnitude of the child’s velocity with respect to the ground can be found,
[tex]v_{cG}=-\vec{V_{cb}}+\vec{v_{bG}}[/tex]
[tex]v_{cG}=-4i+2i[/tex]
[tex]v_{cG}=-2i\ km/h[/tex]
The magnitude of the child’s velocity with respect to the ground is
[tex]v_{cG}=|\vec{v_{cG}}|=-2\ km/h[/tex]
(d). The direction of the child’s velocity with respect to the ground is in negative x-axis.
Hence, (A). The magnitude and direction of the boat's velocity with respect to the ground is 2 km/h in positive x-axis.
(B). The magnitude and direction of the child’s velocity with respect to the ground is 2 km/h in negative x-axis.