Answer:
Option B: [tex]\frac{5+a}{a-1}[/tex]
Step-by-step explanation:
Given function is:
[tex]f(x) = \frac{3+x}{x-3}[/tex]
In order to find f(a+2), we have to put a=2 in place of x in the function
So,
[tex]f(a+2) = \frac{3 + (a+2)}{(a+2)-3}\\ =\frac{3+a+2}{a+2-3}\\ = \frac{5+a}{a-1}[/tex]
Hence, we can see that option b is correct ..