If
[tex]f(x) = \frac{(3 + x)}{x - 3} [/tex]
what is
[tex]f(a + 2)[/tex]
?

a)
[tex] \frac{3 + f(a + 2)}{f(a) - 1} [/tex]
b)
[tex] \frac{(5 + a)}{(a - 1)} [/tex]
c)
[tex] \frac{(3 + a)}{(a - 3)} + 2[/tex]

Respuesta :

Answer:

Option B: [tex]\frac{5+a}{a-1}[/tex]

Step-by-step explanation:

Given function is:

[tex]f(x) = \frac{3+x}{x-3}[/tex]

In order to find f(a+2), we have to put a=2 in place of x in the function

So,

[tex]f(a+2) = \frac{3 + (a+2)}{(a+2)-3}\\ =\frac{3+a+2}{a+2-3}\\ = \frac{5+a}{a-1}[/tex]

Hence, we can see that option b is correct ..

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