Question

What is the power of a motor that can accelerate a 1700 kg car from rest to 30.0 m S in 5.0 seconds?

Answer 1

Answer:

The power of the motor is 153000 watts.

Explanation:

It is given that,

Mass of the car, m = 1700 kg

Initially, it is at rest, u = 0

Final velocity of the car, v = 30 m/s

Time taken, t = 5 s

We need to find the power of a motor. Work done per unit time is called power of the motor. We know that the change in kinetic energy is equal to the work done i.e.

$P=\dfrac{W}{t}=\dfrac{\Delta E}{t}$

$P=\dfrac{\dfrac{1}{2}mv^2}{t}$

$P=\dfrac{\dfrac{1}{2}\times 1700\ kg\times (30\ m/s)^2}{5\ s}$

P = 153000 watts

So, the power of the motor is 153000 watts. Hence, this is the required solution.