Answer:
Speed of car A is half the speed of car B.
Explanation:
Kinetic energy, [tex]KE=\frac{1}{2}mv^2[/tex]
Car A has twice the mass of car B.
[tex]m_A=2m_B[/tex]
Car A has the half the kinetic energy of car B
[tex]KE_A=\frac{1}{2}KE_B[/tex]
We have
[tex]KE_A=\frac{1}{2}KE_B\\\\\frac{1}{2}m_Av_A^2=\frac{1}{2}\times \frac{1}{2}m_Bv_B^2\\\\\frac{1}{2}\times 2m_Bv_A^2=\frac{1}{2}\times \frac{1}{2}m_Bv_B^2\\\\v_A^2=\frac{v_B^2}{4}\\\\v_A=\frac{v_B}{2}[/tex]
Speed of car A is half the speed of car B.