Find the vertex:
[tex]\textrm{Use the formula } \frac{-b}{2a} \textrm{ to find the vertex}\\ \\ \frac{-10}{2} = -5\\ \\ \textrm{In order to find the y value plug in -5 back into the function}\\ \\ y=(-5)^2+10(-5)+16\\ y=-9\\\\ \textrm{The vertex of the function is} (-5,-9)[/tex]
Determine if the parabola will open up or down:
[tex]a > 0 \\ \\ 1>0[/tex]
Since the value of a is positive, the parabola will open upwards
Find the x and y intercepts:
Factor [tex]y = x^2+10x + 16[/tex] to find the x intercepts
(x+8)(x+2)
x + 8 = 0
x = -8
x + 2 = 0
x = -2
x intercepts:
x = -2
x = -8
Find the y intercept
[tex]y = 0^2+10(0) + 16\\\\ y=16[/tex]
Hence, C. Graph A best represents the quadratic function [tex]y = x^2+10x + 16[/tex]