Question

Given the following equation: 4 NH3 (g)5 O2 (g) > 4 NO (g) 6 H20 () + How many moles of H20 is produced if 0.44 mol of NH3 reacts?

Answer 1

Answer : The number of moles of $H_2O$ produced are, 0.66 mole.

Explanation : Given,

Given moles of $NH_3$ = 0.44 mole

The given balanced chemical reaction is,

$4NH_3(g)+5O_2(g)\rightarrow 4NO(g)+6H_2O(g)$

From the given balanced chemical reaction, we conclude that

As, 4 moles of $NH_3$ react to give 6 moles of $H_2O$

So, 0.44 moles of $NH_3$ react to give $\frac{6}{4}\times 0.44=0.66$ moles of $H_2O$

Therefore, the number of moles of $H_2O$ produced are, 0.66 mole.