Question

Find b. given that a = 20, angle A= 30°, and angle B = 45° in triangle ABC.
a = 20
300
45
10_2
20/2
20/3
4022

Answer 1

Answer:

The value of b is 28.28

Step-by-step explanation:

We would use Law of sines to find the value of b

The law of sines is:

$\frac{a}{sinA}=\frac{b}{sinB}$

We are given

a= 20

A = 30°

B = 45°

b=?

Putting values in the formula:

$\frac{20}{sin(30)}=\frac{b}{sin(45)}\\\frac{20}{0.5}=\frac{b}{0.707}\\b = \frac{20}{0.5} * 0.707\\b = 40 * 0.707\\b= 28.28$

The value of b is 28.28