Answer:
[tex]f(x)=7(b)^{x}-2[/tex]
[tex]f(x)=-5(b)^{x}+10[/tex]
Step-by-step explanation:
we know that
The y-intercept is the value of y when the value of x is equal to zero
Verify each case
case 1) we have
[tex]f(x)=7(b)^{x}-2[/tex]
so
For x=0
[tex]f(0)=7(b)^{0}-2[/tex]
[tex]f(0)=7(1)-2=5[/tex]
therefore
The function has a y-intercept of (0,5)
case 2) we have
[tex]f(x)=3(b)^{x}-5[/tex]
so
For x=0
[tex]f(0)=3(b)^{0}-5[/tex]
[tex]f(0)=3(1)-5=-2[/tex]
therefore
The function does not have a y-intercept of (0,5)
case 3) we have
[tex]f(x)=5(b)^{x}-1[/tex]
so
For x=0
[tex]f(0)=5(b)^{0}-1[/tex]
[tex]f(0)=5(1)-1=4[/tex]
therefore
The function does not have a y-intercept of (0,5)
case 4) we have
[tex]f(x)=-5(b)^{x}+10[/tex]
so
For x=0
[tex]f(0)=-5(b)^{0}+10[/tex]
[tex]f(0)=-5(1)+10=5[/tex]
therefore
The function has a y-intercept of (0,5)
case 5) we have
[tex]f(x)=2(b)^{x}+5[/tex]
so
For x=0
[tex]f(0)=2(b)^{0}+5[/tex]
[tex]f(0)=2(1)+5=7[/tex]
therefore
The function does not have a y-intercept of (0,5)