Answer:
132 m².
Step-by-step explanation:
What's the surface area of each lateral face of this pyramid?
Each lateral face of this pyramid is a triangle, with
- a height of 8 meters
- on a base 6 meters.
The base of this pyramid is a square. As a result, all four lateral sides are congruent. The area of each of these triangle is thus
[tex]\displaystyle \frac{1}{2}\times \text{Base}\times \text{Height} = \rm \frac{1}{2} \times 6 \times 8 = 24\; m^{2}[/tex].
The base of this pyramid is a square. The length of a side of this square is 6 meters. The area of the base will be
[tex]\text{Side}^{2} = \rm 6^{2} = 36\; m^{2}[/tex].
Put the five faces together to get the total surface area of this square pyramid:
[tex]\rm 4\times 24 + 36 = 132\; m^{2}[/tex].
