Question

A 6.00 V battery has an internal resistance of 0.8322 What is the terminal voltage if it is connected in series to a circuit with a total resistance of 7380 O 5.89 V O 591V 5.87V O 5.99

Answer 1

Answer:

The terminal voltage will be 5.99 volt.

(d) is correct option.

Explanation:

Given that,

Voltage = 6.00

Internal r= 0.8322 ohm

Total resistance R =7380 ohm

We need to calculate the current

Using current formula

$I=\dfrac{V}{R+r}$

Put the value into the formula

$I = \dfrac{6}{7380+0.8322}$

$I=0.000812\ A$

We need to calculate the voltage drop due to internal resistance

$V' = Ir$

$V'=0.000812\times0.8322$

$V'=0.00067\ volt$

Now, The terminal voltage will be

$V''=6-V'$

$V''=6-0.00067$

$V''=5.99\ volt$

Hence, The terminal voltage will be 5.99 volt,