A tennis ball is shot vertically upward in an evacuated chamber inside a tower with an initial speed of 20.0 m/s at time t = 0 s. Approximately how long does it take the tennis ball to reach its maximum height?

Respuesta :

Answer:

Time taken to reach its maximum height is 2.04 seconds.

Explanation:

It is given that, a tennis ball is shot vertically upward in an evacuated chamber inside a tower with an initial speed of 20.0 m/s at time t = 0 s.

At maximum height, its final velocity v = 0

Let t is the time taken by the tennis ball to reach its maximum height. We know that for a freely falling object, the value of acceleration is -g or -9.8 m/s².

Using first equation of motion as :

[tex]v=u+at[/tex]

[tex]t=\dfrac{v-u}{a}[/tex]

[tex]t=\dfrac{0-20\ m/s}{-9.8\ m/s^2}[/tex]

t = 2.04 seconds

Therefore, this is the required solution.

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