Question

bullet of mass 0.02070 �� collides inelastically with a wooden block of mass 28.00 ��, initially at rest. After the collision the, system has speed of 1.180 �/�. (a) What was initial speed of the bullet

Answer 1

Explanation:

It is given that,

Mass of bullet, m₁ = 0.0207 kg

Mass of wooden block, m₂ = 28 kg

Wooden block is initially at rest, u₂ = 0 m/s

After the collision the, system has speed of, v = 1.180 m/s

We need to find the initial speed (u₁) of the bullet. It can be calculated using the conservation of linear momentum as :

$m_1u_1+m_2u_2=(m_1+m_2)v$

$0.0207\ kg\times u_1+0=(0.0207\ kg+28\ kg)\times 1.180\ m/s$

$0.0207\times u_1=33.06$

$u_1=1597.10\ m/s$

So, the initial speed of the bullet is 1597.10 m/s. Hence, this is the required solution.