Question

What is the simplest form of the expression below?

$\frac{x^2yz}{y^2}$×$\frac{y}{2x}$

A. $\frac{xz}{2}$
B. $\frac{2x^3z}{y^2}$
C. $\frac{x^2z}{2y^2x}$
D. z

Answer 1

Answer:

$\text{A.}\quad\dfrac{xz}{2}$

Step-by-step explanation:

$\dfrac{x^2yz}{y^2}\times\dfrac{y}{2x}=\dfrac{x^2yzy}{2xy^2}=\dfrac{1}{2}\cdot\dfrac{x^2}{x}\cdot\dfrac{y^2}{y^2}\cdot\dfrac{z}{1}\\\\=\dfrac{xz}{2}$