Respuesta :
Answer:
Option b: 6√3
Step-by-step explanation:
Given expression is:
[tex]\sqrt{36*3}[/tex]
We have to factorize the radicand in order to solve the given radical
So,
[tex]= \sqrt{3*3*2*2*3}[/tex]
In order to solve the square root pairs are made:
[tex]=\sqrt{2^2 * 3^2 * 3}[/tex]
To evaluate the square root, the exponents are multiplied by 1/2
[tex]= 2^{(2*\frac{1}{2})} *3^{(2*\frac{1}{2})} * 3^{(\frac{1}{2})}\\=2*3*\sqrt{3} \\=6\sqrt{3}[/tex]
Hence, option b is correct ..