Question

You are playing with a standard deck of 52 playing cards. Each time you draw one card from the deck, and then you put the card back, and reshuffle the deck before choosing another card. What is the probability of selecting a number less than (but not including) 4? Count aces as equal to 1. (report a number rounded to the nearest two decimal places, but not a fraction)

Answer 1

Answer:

0.23

Step-by-step explanation:

A standard deck has 4 suits (spade, club, diamond, and heart), and each suit has 13 ranks (ace, 2, 3, 4, 5, 6, 7, 8, 9, 10, jack, queen, and king).

We want to know the probability of drawing an ace, a 2, or a 3.  There are four aces, four 2's, and four 3's in a deck (one for each suit).  That's a total of 12 cards.  So the probability is:

12 / 52 ≈ 0.23

Answer 2

Using the probability concept, it is found that there is a 0.2308 = 23.08% probability of selecting a number less than 4.

--------------------------

• A probability is the division of the number of desired outcomes by the number of total outcomes.
• In a standard deck, there are 52 cards, and thus, the number of total outcomes is $T = 52$
• Of those, 12 are less than 4, and thus, the number of desired outcomes is $D = 4$.

Thus, the probability of selecting a number less than 4 is:

$p = \frac{D}{T} = \frac{12}{52} = 0.2308$

0.2308 = 23.08%

A similar problem is given at https://brainly.com/question/13484439