Question

An elbow has a loss coefficient K of 0.4. Considering a pipe with friction factor of 0.025 and diameter of 20 mm, what is the equivalent length (Le) for the elbow in mm?

Answer 1

Answer:

320 mm

Explanation:

The equivalent length for a minor loss is:

Le = K D / f

where K is the loss coefficient, D is the diameter, and f is the friction factor.

Le = (0.4) (20 mm) / 0.025

Le = 320 mm