A half-filled cylindrical water tank has a water level of 20 feet high. The tank can hold 6000 cubic feet of water. Find the diameter of the tank in feet to the nearest tenth

Respuesta :

Answer:

[tex]D=13.8\ ft[/tex]

Step-by-step explanation:

we know that

If the tank half-filled with water is at 20 feet, then the height of the tank is 40 feet

The volume of the cylindrical tank is equal to

[tex]V=\pi r^{2}h[/tex]

we have

[tex]h=40\ ft[/tex]

[tex]V=6,000\ ft^{3}[/tex]

assume

[tex]\pi =3.14[/tex]

substitute and solve for r

[tex]6,000=(3.14)r^{2}(40)[/tex]

[tex]r^{2}=6,000/[(3.14)(40)][/tex]

[tex]r=6.9\ ft[/tex]

Find the diameter

Remember that the diameter is two times the radius

[tex]D=6.9*2=13.8\ ft[/tex]

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