Question

The distance between two successive minima of a transverse wave is 3.10 m. Five crests of the wave pass a given point along the direction of travel every 14.7 s. (a) Find the frequency of the wave. Hz (b) Find the wave speed. m/s

Answer 1

Answer:

The frequency is 0.34 Hz and the wave speed is 1.05 m/s.

Explanation:

Given that,

The distance between two successive minima of a transverse wave is wavelength.

Wavelength = 3.10 m

Time = 14.7 s

(I). We need to calculate the frequency

$f=\dfrac{number\ of\ wave\ propagated\ per\ second }{times}$

$f=\dfrac{5}{14.7}$

$f=0.34\ Hz$

(II). We need to calculate the wave speed

Formula of wave speed

$v= \lambda\times f$

Where,

$\lambda = wavelength$

$f = frequency$

Put the value into the formula

$v=3.10\times0.34$

$v=1.05\ m/s$

Hence, The frequency is 0.34 Hz and the wave speed is 1.05 m/s.