Question

T^3: (x,y) —>
Options are in the picture

Answer 1

I think there is a rule based in there, so Like:

T^1 : (x , y) ------>  (x+3 , y+1)

T^2: (x, y ) -------> (x +3 +3 , y+1+1) = (x+6, y+2)

So I think T^3 should be:

T^3: (x, y) -------> ( x+3+3+3 , y+1+1+1) = (x+9, y+3)

So the answer should be the 2nd.