Answer:
Step-by-step explanation:
The intercept form of a quadratic equation y = ax² + bx + c:
[tex]y=a(x-p)(x-q)[/tex]
[tex]\text{x-intercepts:}\ p\ \text{and}\ q\\\\\text{y-intercept}:\ a(-p)(-q)[/tex]
We have the equation:
[tex]y=2x^2-9x-5=(2x+1)(x-5)[/tex]
[tex]2x+1=2\left(x+\dfrac{1}{2}\right)\to y=2\left(x+\dfrac{1}{2}\right)(x-5)[/tex]
[tex]y=2\bigg(x-\left(-\dfrac{1}{2}\right)\bigg)(x-5)[/tex]
Therefore
[tex]a=2\\\\x-intercepts:\ p=-\dfrac{1}{2}\ \text{and}\ q=5\\\\\text{y-intercept:}\ (2)\left(-\dfrac{1}{2}\right)(5)=-5[/tex]