Question

2(n-1)+4n=2(3n-1)

n=0

no solution

infinitely many solutions

n= - 4




HELP PLEASE!!!!!!!​

Answer 1

Answer:

Infinitely many solutions.

Step-by-step explanation:

2 (n - 1) + 4n = 2 (3n - 1) Let's simplify this to solve it.

2n - 2 + 4n = 6n - 2 Distribute 2(n-1) and 2(3n-1)

2n + 4n - 2 = 6n - 2 Rearrange the left side of the equation.

6n - 2 = 6n - 2 Add 2n + 4n.

-6n        -6n Subtract 6n from both sides.

-2 = -2? Yes, -2 equals -2.

Therefore, the answer is infinitely many solutions, meaning that n can be any real number.

Answer 2

An equation can have no solution, one solution or infinitely many solutions.

The equation $2(n -1) + 4n = 2(3n - 1)$ has infinitely many solutions

Given that:

$2(n -1) + 4n = 2(3n - 1)$

Open brackets

$2n -2 + 4n = 6n - 2$

Collect like terms

$2n + 4n - 6n= - 2+2$

$0 = 0$

When the solution to an equation is 0 on both sides, the equation has infinitely many solutions

Read more about number of solutions at:

https://brainly.com/question/15272411