Respuesta :
recall your d = rt, distance = rate * time.
s = Samantha's speed rate
one thing to bear in mind is that, when Samantha is going upstream, she's not really going "s" mph fast, because she's going against the current, and the current's rate is 4 mph and subtracting speed from her, then she's really going "s - 4" fast.
Likewise, when she's going downstream because she's going with the current, the current is adding speed to her, so she's going "s + 4" fast.
Now, let's say the distance she covered both ways was the same "d" miles.
Let's recall that since there are 60 minutes in 1 hour, 12 minutes is 12/60 = 1/5 of an hour.
[tex]\bf \begin{array}{lcccl} &\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{hours}{time}\\ \cline{2-4}&\\ Upstream&d&s-4&1\\ Downstream&d&s+4&\frac{1}{5} \end{array}\qquad \implies \begin{cases} d=(s-4)(1)\\ d=(s+4)\left( \frac{1}{5} \right) \end{cases} \\\\[-0.35em] ~\dotfill[/tex]
[tex]\bf \stackrel{\textit{from 1st equation}}{\boxed{d}=s-4}\qquad \qquad \stackrel{\textit{substituting on the 2nd equation}~\hfill }{\boxed{s-4}=\cfrac{s+4}{5}\implies 5s-20=s+4} \\\\\\ 4s-20=4\implies 4s=24\implies s=\cfrac{24}{4}\implies s=6[/tex]
Answer:
6 mph
Step-by-step explanation:
Let the the total distance is D and the speed of Samantha's speed in still water is x ( in mph ),
Here, speed of stream = 4 mph,
Thus, the speed in upstream = (x - 4) mph,
Speed in downstream = (x + 4) mph,
We know that,
[tex]Speed =\frac{Distance}{Time}\implies Time =\frac{Distance}{Speed}[/tex]
∴ Time taken in upstream = [tex]\frac{D}{x-4}[/tex]
And, time taken in downstream = [tex]\frac{D}{x+4}[/tex]
According to the question,
[tex]\frac{D}{x-4}=1\implies D = x-4-----(1)[/tex]
[tex]\frac{D}{x+4}=\frac{12}{60}\implies \frac{D}{x+4}=\frac{1}{5}\implies 5D=x+4----(2)[/tex]
Equation (1) - 5 equation (2),
0 = x + 4 - 5x + 20
0 = -4x + 24
4x = 24
⇒ x = 6 mph.
Hence, Samantha swims with the speed 6 mph.
