Respuesta :
Answer:
f(x)^-1 = 1/3x - 2
Step-by-step explanation:
Replace f(x) with y and solve:
y = 3x + 6
Swap x and y
x = 3y + 6
Now isolate y
x/3 = 3y/3 + 6/3
1/3 x = y + 2
1/3 x - 2 = y + 2 - 2
y = 1/3x - 2 or f(x)^-1 = 1/3x - 2
For this case we have the following function:
[tex]f (x) = 3x + 6[/tex]
We must find the inverse of the function, then:
Replace f (x) with y:[tex]y = 3x + 6[/tex]
We exchange the variables:
[tex]x = 3y + 6[/tex]
We solve for "y":
Subtracting 6 on both sides of the equation:
[tex]x-6 = 3y[/tex]
Dividing between 3 on both sides of the equation:
[tex]y = \frac {x} {3} - \frac {6} {3}\\y = \frac {x} {3} -2[/tex]
We change y by [tex]f ^ {- 1} (x)[/tex], and finally we have:
[tex]f ^ {- 1} (x) = \frac {x} {3} -2[/tex]
ANswer:
[tex]f ^ {- 1} (x) = \frac {x} {3} -2[/tex]