Question

Given the equation y − 4 = three fourths(x + 8) in point-slope form, identify the equation of the same line in standard form.

−three fourthsx + y = 10
3x − 4y = −40
y = three fourthsx + 12
y = three fourthsx + 10

Answer 1

Answer:

$3x-4y=-40$

Step-by-step explanation:

The standard form of a linear equation is  $ax+by=c$.

The given line has equation:

$y-4=\frac{3}{4}(x+8)$

This is the point-slope form of the given line.

To find the standard form, we clear the fraction

$4y-16=3(x+8)$

We expand the parenthesis now to get:

$4y-16=3x+24$

We group the variables on the LHS and the constants on the RHS.

$4y-3x=24+16$

$-3x+4y=40$

Multiply through by -1

$3x-4y=-40$

This is of the form: $ax+by=c$.