Answer:
[tex]\large\boxed{-5\dfrac{2}{5}=-\dfrac{27}{5}}[/tex]
Step-by-step explanation:
[tex]\bold{Method\ 1}:\\\\5=\dfrac{5\cdot5}{5}=\dfrac{25}{5}\\\\-5\dfrac{2}{5}=-\left(5+\dfrac{2}{5}\right)=-\left(\dfrac{25}{5}+\dfrac{2}{5}\right)=-\dfrac{25+2}{5}=-\dfrac{27}{5}\\\\\bold{Method\ 2:}\\\\\text{Multiply the integer by the denominator and add it to the numerator.}\\\\-5\dfrac{2}{5}=-\dfrac{(5)(5)+2}{5}=-\dfrac{25+2}{5}=-\dfrac{27}{5}[/tex]
