Answer: Graph (-4, -2) and (-2, 1)
Step-by-step explanation:
[tex]\text{The given equation is: }y+2=\dfrac{3}{2}(x+4)\\\\\text{which is of the form: }y-y_1=m(x-x_1)\\\implies(x_1, y_1)=(-4, -2)\quad and \quad m=\dfrac{3}{2}\implies (x+2, y+3)\\\\.\qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad (-4+2, -2+3)=(-2, 1)[/tex]
So, two possible points are (-4, -2) and (-2, 1).
Plot those two coordinates and draw a line through them.
