Answer:
The new volume is 8 times smaller than the original volume
Step-by-step explanation:
we know that
If two figures are similar, then the ratio of its volumes is equal to the scale factor elevated to the cube
Let
z-----> the scale factor
x ----> the volume of the reduced sphere
y ----> the volume of the original sphere
so
[tex]z^{3}=\frac{x}{y}[/tex]
we have
[tex]z=1/2[/tex] ----> scale factor
substitute
[tex](1/2)^{3}=\frac{x}{y}[/tex]
[tex](1/8)=\frac{x}{y}[/tex]
[tex]x=\frac{y}{8}[/tex]
therefore
The new volume is 8 times smaller than the original volume
Verify
The volume of the original sphere is
[tex]r=18/2=9\ cm[/tex] ---> the radius is half the diameter
[tex]V=\frac{4}{3}\pi (9)^{3}=972\pi \ cm^{3}[/tex]
the volume of the reduced sphere is
[tex]r=9/2=4.5\ cm[/tex] ---> the radius is half the diameter
[tex]V=\frac{4}{3}\pi (4.5)^{3}=121.5\pi \ cm^{3}[/tex]
Divide the volumes
[tex]972\pi \ cm^{3}/121.5\pi \ cm^{3}=8[/tex]