Question

What is the measure of each of the two angles formed by the bisector of the diagonal of a rhombus if the original angle measures 58 degrees?

Answer 1

Answer: 29 degrees is the answer

Step-by-step explanation:

The bisector is the line that divides the angle, and rhombus diagonally. So, basically you're just dividing 58 in half. Which is 29 degrees.

Answer 2

The measure of each of the two angles formed by the bisector of the diagonal of a rhombus will be 29 degree.

What is angle ?

Angle is the figure formed by two rays, called the sides of the angle, sharing a common endpoint, called the vertex of the angle.

We have,

A Rhombus with one of its angle equal to 58°.

Now,

Bisector of an angle, divides an angle into two equal parts.

So,

From the above mentioned definition,

i.e.

$=\frac{58}{2} = 29^0$

So, the measure of each angle is 29°.

Hence, we can say that the measure of each of the two angles formed by the bisector of the diagonal of a rhombus will be 29 degree.

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