Question

What is the value of the discriminant, b2 ? 4ac, for the quadratic equation 0 = x2 ? 4x + 5, and what does it mean about the number of real solutions the equation has?

Answer 1

Answer:

Discriminant D = -4 , no real solution

Step-by-step explanation:

Here our equation is

$x^{2}-4x+5=0$

Discriminant (D)= $b^2-4ac$

where

a = coefficient of term containing $x^{2}$

b= coefficient of the term containing $x$

c is the constant term

hence

a=1 , b =-4 and c=5

Hence

$D=b^2-4ac\\D=(-4)^2-4*1*5\\D=16-20\\D=-4$

Hence D is less than 0 , therefore we do not have any real solution to this quadratic equation.

Answer 2

Answer:

b on edge-The discriminant is −4, so the equation has no real solutions.

Step-by-step explanation: