Which of the following shows the graph of y=2e^x?
![Which of the following shows the graph of y2ex class=](https://us-static.z-dn.net/files/d4a/7374d8ebd4bfda3062b9e07ed0998e2d.png)
![Which of the following shows the graph of y2ex class=](https://us-static.z-dn.net/files/ddf/4b2d580a193aff4109c4d0f093d34bc7.png)
![Which of the following shows the graph of y2ex class=](https://us-static.z-dn.net/files/d16/c4219c3e39cd167be270b6b93e500f79.png)
![Which of the following shows the graph of y2ex class=](https://us-static.z-dn.net/files/da8/51cac53f5b36b8a0bb24053fa7fc7afa.png)
Answer:
The third one.
Step-by-step explanation:
When x=0, the function y=2e^x equals:
y=2e^x = 2e^(0) = 2.
For that reason, the graph should cross the y-axis at the point (0, 2). The only graph that meets this requirement is the third one :).
For this case we must indicate the graph corresponding to the following equation:
[tex]y = 2e ^ x[/tex]
Then, we evaluate the equation for[tex] x = 0[/tex]
[tex]y = 2e ^ 0[/tex]
We have by definition, any number raised to zero results in 1.
So:
[tex]y = 2[/tex]
Now we evaluate the equation for x = -1
[tex]y = 2e ^ {-1}\\y = \frac {2} {e}\\y = 0.736[/tex]
We already have two points to graph:
[tex](0,2)\\(-1,0.736)[/tex]
Observing the options, we realize that the correct option is option C.
It should be noted that graphs A and D, by definition, do not correspond to the exponential function.
Answer:
Option C