Answer:
2 2/3 hours
Step-by-step explanation:
The total of the given outage lengths is ...
(1/4) + (2/3) + (1 3/4) = (1/4 + 1 3/4) + 2/3
= 2 + 2/3 = 2 2/3
The water was off for 2 2/3 hours.
Answer: The required number of tireless hours is [tex]2\dfrac{2}{3}~\textup{hours}.[/tex]
Step-by-step explanation: Given that on Monday, the water was shut off 3 times for [tex]\dfrac{1}{4}[/tex] hours, [tex]\dfrac{2}{3}[/tex] hours, and [tex]1\dfrac{3}[4}[/tex] hours, respectively.
We are to find the tireless number of hours for which the water was off.
The tireless number of hours for which the water was off is equal to the sum of the number of hours for which the water was off three times.
Therefore, the number of tireless hours for which the water was off is given by
[tex]n_t\\\\\\=\dfrac{1}{4}+\dfrac{2}{3}+1\dfrac{3}{4}\\\\\\=\dfrac{1}{4}+\dfrac{2}{3}+\dfrac{7}{4}\\\\\\=\dfrac{3+8+21}{12}\\\\\\=\dfrac{32}{12}\\\\\\=\dfrac{8}{3}\\\\\\=2\dfrac{2}{3}.[/tex]
Thus, the required number of tireless hours is [tex]2\dfrac{2}{3}~\textup{hours}.[/tex]
