Answer:
2 x 10⁻¹²F
Explanation:
Capacitance is defined as the ration of charge (q) on either plates to the potential difference V between them.
C = [tex]\frac{q}{V}[/tex]
Where q is the charge on the plates
V is the potential difference
From the given parameters:
Charge on plate, q = 2.0 x 10⁻¹⁰C
Potential difference across the plate = 100V
Unknown parameter:
Capacitance of the system = ? = C
Solution
Capacitance = 2.0 x 10⁻¹⁰/100 = 2 x 10⁻¹²F