A. 8pi
B. pi
C. 2pi
D. 4pi
![A 8pi B pi C 2pi D 4pi class=](https://us-static.z-dn.net/files/dd8/3f0d839b8a84c81a10c49afe3645d2dd.png)
Answer: Option C
[tex]AC = 2\pi[/tex]
Step-by-step explanation:
The arc length is calculated as
[tex]L = \theta * R[/tex]
Then
[tex]AC = \theta * R[/tex]
We know that
[tex]BC = 24\ ft[/tex]
If BC is the diameter of the circumference then the radius R is:
[tex]R = \frac{BC}{2}[/tex]
[tex]R = \frac{24}{2}[/tex]
[tex]R = 12\ ft[/tex]
Now we convert the anglo from degrees to radians[tex]\theta= 30\° * \frac{\pi}{180\°}\\\\\theta=\frac{1}{6}\pi[/tex]
Finally
[tex]AC = \frac{1}{6}\pi * 12[/tex]
[tex]AC = 2\pi[/tex]
Answer:
The length of the arc AC is 2π ⇒ answer C
Step-by-step explanation:
* Lets revise some facts in the circle
- The length of the arc is depends on the measure of the arc and the
radius of the circle
- The length of the arc is a part of the length of the circle
- The length of the circle is 2πr
- The rule of the length of the arc = [tex]\frac{\alpha }{360}*2\pi r[/tex],
where α is the measure of the arc
* Now lets solve the problem
- In circle P
∵ BC is a diameter
∵ BC = 24 ft
∵ The length of the radius of the circle is 1/2 the length of the diameter
∴ The length of the radius = 1/2 × 24 = 12 ft
- Ac is an arc in the circle
∵ The measure of the arc = 30°
∵ The length of the arc = [tex]\frac{\alpha }{360}*2\pi r[/tex] ,
where α is the measure of the arc
∴ α = 30°
∵ r = 12 ft
∴ The length of the arc = [tex]\frac{30}{360}*2(12)\pi=\frac{1}{12}*(24)\pi=2\pi[/tex]
∴ The length of the arc AC is 2π