Question

The turning point of the curve: y=6-4x-x^2​

Answer 1

Answer:

The turning point is (-2,10)

Step-by-step explanation:

we have

$y=6-4x-x^{2}$

This is a quadratic equation (vertical parabola) open downward

we know that

The turning point of a quadratic equation is the vertex

so

Convert the quadratic equation into vertex form

$y-6=-4x-x^{2}$

$y-6=-(x^{2}+4x)$

$y-6-4=-(x^{2}+4x+4)$

$y-10=-(x^{2}+4x+4)$

$y-10=-(x+2)^{2}$

$y=-(x+2)^{2}+10$ ----> equation in vertex form

The vertex is the point (-2,10)

therefore

The turning point is (-2,10)