Answer:
Step-by-step explanation:
[tex]\dfrac{x}{5}+1=7\qquad\text{subtract 1 from both sides}\\\\\dfrac{x}{5}+1-1=7-1\\\\\dfrac{x}{5}=6\qquad\text{multiply both sides by 5}\\\\5\!\!\!\!\diagup^1\cdot\dfrac{x}{5\!\!\!\!\diagup_1}=5\cdot6\\\\x=30[/tex]