Answer:
The point is (3 , 6)
Step-by-step explanation:
* Lets explain how to solve this problem
- We want to reflect the point (x , y) across the line y = a, where a
any constant
- The line y = a is a horizontal line, means parallel to x-axis
- We will change the y-coordinates only because we will move
up and down
- We will move the point and the line by a units down if a is positive
or up if a is negative to make the line is the x-axis and also move the
point by a units as the line
- Then we will reflect the new point across the x-axis means we will
change the sign of y-coordinate
- After that we will add the value of a again to the y-coordinate to
the point after reflection
* Lets solve the problem
∵ The point is (3 , 4)
∵ The point will reflect across the line y = 5
- We take the line 5 units down to be the x-axis and also we will take
the point down 5 units
∴ The point = (3 , 4 - 5) = (3 , -1)
- Now reflect the point across the x-axis by change the sign of the
y-coordinate
∴ The new point is (3 , 1)
- Now add the y-coordinate of the new point the 5 units which we
subtracted before
∴ The image of the point P after reflection across the line y = 5 is
(3 , 1 + 5) = (3 , 6)
* The point is (3 , 6)
