Question

What is the distance between the points (-4,2) and (1,-3) on the coordinate points? WILL GIVE BRAINIEST ANSWER HELP ASAP

Answer 1

For this case we have that by definition, the distance between two points is given by:

$d = \sqrt {(x_ {2} -x_ {1}) ^ 2+(y_ {2} -y_ {1}) ^ 2}$

We have the following points:

$(x_ {1}, y_ {1}) = (- 4,2)\\(x_ {2}, y_ {2}) = (1, -3)$

Substituting we have:

$d = \sqrt {(1 - (- 4)) ^ 2+(-3-2) ^ 2}\\d = \sqrt {(1 + 4) ^ 2+(-5) ^ 2}\\d = \sqrt {(5) ^ 2+(-5) ^ 2}\\d = \sqrt {25 + 25}\\d = \sqrt {50}\\d = 7.07units$

Answer:

Option B

Answer 2

Answer: Option B

$d=7.07$

Step-by-step explanation:

The distance between two points is calculated using the following formula

$d=\sqrt{(x_1-x_0)^2+(y_1-y_0)^2}$

In this problem we have the following points

(-4,2) and (1,-3)

Therefore

$x_0=-4\\y_0 = 2\\x_1=1\\y_1=-3$

Then the distance d is:

$d=\sqrt{(1-(-4))^2+((-3)-2)^2}$

$d=\sqrt{(1+4)^2+(-3-2)^2}$

$d=\sqrt{(5)^2+(-5)^2}$

$d=\sqrt{50}$

$d=5\sqrt{2}$

$d=7.07$