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Which functions C(x) represents the monthly cost in dollars in terms of x, the number of gigabytes used in a month

Which functions Cx represents the monthly cost in dollars in terms of x the number of gigabytes used in a month class=

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Answer:

The answer in the procedure

Step-by-step explanation:

Let

x ----> the number of gigabytes used in a month

C(x)------> the monthly cost in dollars

step 1

For the interval ----> [0,2]

[tex]0\leq x\leq 2[/tex]

[tex]C(x)=15[/tex]

step 2

For the interval ---->(2,6]

[tex]2< x\leq 6[/tex]

Find the equation of the line

Find the slope

we have

[tex](2,20),(6,40)[/tex]

[tex]m=(40-20)/(6-2)=5[/tex]

The equation of the line in to point slope form is equal to

[tex]y-20=5(x-2)\\ y=5x-10+20\\ y=5x+10[/tex]

therefore

[tex]C(x)=5x+10[/tex]

step 3

For the interval ----> (6,∞]

[tex]x> 6[/tex]

[tex]C(x)=50[/tex]

Answer:

C(x)=[tex]15, 0\leq x\leq 2[/tex]

        [tex]5x+10, 2<x\leq 6[/tex]

          [tex]50, [/tex] 6<x≤∞

Step-by-step explanation:

C(x) represents the monthly cost in dollars in terms of x, the number of gigabytes used in a month

Lets find C(x) on each interval (for every line graph)

first interval 0 to 2

the value of y is 15 on the interval 0 to 2

Its horizontal line . So equation is c(x)=the constant y value

[tex]C(x)= 15, 0\leq x\leq 2[/tex]

Second interval 2 to 6

Pick two points to get the equation of that line

(3,25) and (6,40)

[tex]slope = \frac{y_2-y_1}{x_2-x_1} =\frac{40-25}{6-3} =5[/tex]

Equation of the line is using m=5 and (3,25)

[tex]y-y1=m(x-x1)[/tex]

[tex]y-25=5(x-3)[/tex]

[tex]y-25=5x-15[/tex]

[tex]y=5x+10[/tex]

[tex]C(x)= 5x+10, 2<x\leq 6[/tex]

Now we look at the third interval

6 to infinity

For the third graph , the value of y is 50 (constant)

It is a horizontal line

So [tex]C(x)= 50, [/tex] 6<x≤∞

We got three equations for C(x)

C(x) is a piecewise function

C(x)=[tex]15, 0\leq x\leq 2[/tex]

        [tex]5x+10, 2<x\leq 6[/tex]

          [tex]50, [/tex] 6<x≤∞

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