Question

What is the slope of the line defined by the parametric equations x=-2+4t and y=1+4t ?

Answer 1

Answer:

The value of slope m = -1

Step-by-step explanation:

x = -2 + 4t

and y = 1 + 4t

Solving the both equations

x +2 = 4t

=> t = (x+2)/4     eq(1)

y-1 = 4t

=> t = (y-1)/4      eq(2)

Putting eq(1) = eq(2) as left hand side of both equations are same

(x+2)/4 = (y-1)/4

Cross multiplying

4(x+2) = 4(y-1)

4x + 8 = 4y -4

4x +4y = -4 -8

4x + 4y = -12

4(x+y) = -12

x+y = -12/4

x+y = -3

y = -x -3

The slope intercept form of line is:

y = mx + b

where m is the slope. Comparing with y = -x-3

The value of slope m = -1

Answer 2

The slope of the line defined by the parametric equations x=-2+4t and y=1+4t is mathematically given as

m = -1

What is the slope of the line defined by the parametric equations x=-2+4t and y=1+4t ?

Question Parameter(s):

the parametric equations x=-2+4t and y=1+4t

Generally, the equation for the Equations   is mathematically given as

x=-2+4t

y=1+4t

Therefore

t = (x+2)/4..1

t = (y-1)/4 ...2

 Hence

(x+2)/4 = (y-1)/4

4(x+2) = 4(y-1)

y = -x -3

In conclusion, slope intercept

y = mx + b

Hence

y = -x-3

The slope is m = -1

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