Solve: 12x^2+5x-4=12^2x+6
![Solve 12x25x4122x6 class=](https://us-static.z-dn.net/files/d97/4a79c5935c2ea752f716cb4f520eb8d0.png)
okay so we need to solve for x.
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FIRST STEP: 12x^2+5x-4=12^2x+6 would turn into x2 + 5x - 4 = 2x + 6 so it'd have equal bases.
SECOND STEP: move any number with "x" in it to the left side. it ends up as x2 + 3x - 4 = 6
THEN, we use the AC method to eliminate any unnecessary numbers.
you should end up with ( x - 2) (x + 5) = 0
SO, the answer is your third option. ( x = 2, x = -5)
Answer:
x=-5&x=2
Step-by-step explanation:
Since the bases on both sides of the equation are the same, they will cancel each other leaving the exponents
x²+5x-4 = 2x + 6
Collect like terms
x²+5x-2x-4-6=0
x²+3x-10=0
The highest power is 2 , so factorize
x²+5x-2x-10=0
x(x+5)-2(x+5)=0
(x+5)(x-2)=0
x = -5 or x = 2
Check
When x = -5
-5²+3*-5-10=0
25-15-10 =0
0=0
:.x=-5
When x=2
2²+3*2-10=0
4+6-10=0
0=0