Answer: [tex]\sqrt{32}\text{ mi}[/tex]
Step-by-step explanation:
The Pythagoras theorem of right triangle says that the square of the hypotenuse is equal to the sum of the squares of the other two sides.
From the given figure , the hypotenuse of the right triangle = [tex]\sqrt{113}\text{ mi}[/tex]
Then According to Pythagoras theorem , we have
[tex](\sqrt{113})^2=x^2+(9)^2\\\\\Rightarrow\ x^2=113-81\\\\\Rightarrow\ x^2=32\\\\\Rightarrow\ x=\sqrt{32}\text{ mi}[/tex]
