Question

Find three consecutive even integers whose sum is −24

Answer 1

For this case we have that the sum of 3 consecutive integers is 24, if we represent by means of an equation we have:

$x + (x + 2) + (x + 4) = - 24\\x + x + 2 + x + 4 = -24\\3x + 6 = -24\\3x = -24-6\\x = \frac {-30} {3}\\x = -10$

Thus, the three consecutive numbers are:

$x = -10\\x = -10 + 2= -8\\x = -10 + 4 = -6$

Answer:

-10,-8,-6

Answer 2

Answer: $-10,-8,-6$

Step-by-step explanation:

Let be:

 $x$, $x+2$ and  $x+4$ the three consecutive even integers whose sum is -24

Then, we can write this expression:

 $x+(x+2)+(x+4)=-24$

Now, we must solve for "x":

$3x+6=-24\\\\3x=-24-6\\\\3x=-30\\\\x=\frac{-30}{3}\\\\x=-10$

Then you get that the others integers are:

$x+2=-10+2=-8$

$x+4=-10+4=-6$

Therefore, the  three consecutive even integers whose sum is -24 are:

$-10,-8,-6$