Question

Sue travels by bus or walks when she visits the shops. The probability that she catches the bus to the shops is 0.4. The probability she catches the bus from the shops is 0.7. Show the probability that Sue walks at one way is 0.72

Answer 1

Answer:

Proved,

P(A∪B)=0.72

Step-by-step explanation:

Sue travels by bus or walks when she visits the shops.

Probability( catch the bus to the shop ), P(A) = 0.4

Probability( catch the bus from the shop ), P(B) = 0.7

Both A and B are independent events.

Therefore,

P(A∩B) = 0.4×0.7

           = 0.28

Probability Sue walks one way = 1 - P(A∩B)

                                                   = 1 - 0.28

                                                   = 0.72

Hence, the probability that Sue walks at one way is 0.72

Answer 2

The probability that Sue walks one way is 0.72 and this can be determined by using the properties of probability and the given data.

Given :

• Sue travels by bus or walks when she visits the shops.
• The probability that she catches the bus to the shops is 0.4.
• The probability she catches the bus from the shops is 0.7.

Let the probability that Sue catches the bus be P(A) and the probability that she catches the bus from the shops be P(B).

P(A) = 0.4

P(B) = 0.7

$\rm P(A\cap B) = P(A)\times P(B)$

$\rm P(A\cap B) = 0.4\times 0.7$

$\rm P(A\cap B) = 0.28$

Now, the probability that Sue walks at one way is given by:

$=\rm 1 -P(A\cap B)$

= 1 - 0.28

= 0.72

Therefore, the probability that Sue walks at one way is 0.72.

For more information, refer to the link given below:

https://brainly.com/question/23017717