Answer: [tex]\dfrac{9}{10}[/tex]
Step-by-step explanation:
From the table , the total number of numbers = 10
The group of 5 digits contain less than or equal to 2 even digits = 55170
i.e. The total group of 5 digits contain at least 2 =[tex]10-1=9[/tex]
Now, the probability that a group of 5 random digits will contain at least 2
even digits is given by :-
[tex]=\dfrac{\text{Favorable outcomes}}{\text{Total outcomes}}=\dfrac{9}{10}[/tex]
Hence, the probability that a group of 5 random digits will contain at least 2 even digits [tex]=\dfrac{9}{10}[/tex]
