Question

Triangle QRS has vertices Q(8, –6), R(10, 5), and S(–3, 3). What are the coordinates of the vertices of the image of the triangle after a translation of T–7.6, 4.3(x, y)?

Answer 1

Answer:

Q'(0.4,-1.7),R'(2.4,9.3), S'(-10.6,7.3)

Step-by-step explanation:

we know that

The rule of the translation is equal to

(x,y) -----> (x-7.6,y+4.3)

That means---> the translation is 7.6 units left and 4.3 units up

Find the coordinates of the vertices of the image

Q(8,-6) -----> Q'(8-7.6,-6+4.3)

Q(8,-6) -----> Q'(0.4,-1.7)

R(10,5) -----> R'(10-7.6,5+4.3)

R(10,5) -----> R'(2.4,9.3)

S(-3,3) -----> S'(-3-7.6,3+4.3)

S(-3,3) -----> S'(-10.6,7.3)

Answer 2

The coordinates of the vertices Q, R, and S of the image of the triangle after a translation are (0.4, -1.7), (2.4, 9.3), and (-10.6, 7.3)

Translation is a way of changing the location of an object on the xy plane.

Given the vertices of the triangle QRS as

Q(8, –6)

R(10, 5)

S(–3, 3)

If the coordinate of the vertices is translated under the rule (x–7.6, y+4.3)

For Q'

Q' = (8-7.6, -6+4.3)

Q' = (0.4, -1.7)

For R':

Q' = (10-7.6, 5+4.3)

Q' = (2.4, 9.3)

For the coordinate S'

S' = (-3-7.6, 3+4.3)

S' = (-10.6, 7.3)

Hence the coordinates of the vertices Q, R, and S of the image of the triangle after a translation are (0.4, -1.7), (2.4, 9.3), and (-10.6, 7.3)

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