At Which values of x does the function f(x) have a vertical asymptote? Check all that apply
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Answer:
C, D and E
Step-by-step explanation:
The denominator of f(x) cannot be zero as this would make f(x) undefined.
Equating the denominator to zero and solving gives the values that x cannot be and if the numerator is non zero for these values then they are vertical asymptotes.
solve 3x(x - 1)(x + 5) = 0
Equate each factor to zero and solve for x
3x = 0 ⇒ x = 0
x - 1 = 0 ⇒ x = 1
x + 5 = 0 ⇒ x = - 5
Vertical asymptotes at x = -5, x = 1 and x = 0