Question

What is Steven’s slugging average if his stats are- Show steps. 25 singles 10 doubles 3 triples 10 homeruns 140 at-bats


a. 25 + 10 + 3 + 10 = 48/140 = .3428


b. 25(.1) + 10(.2) + 3(.3) + 10(.4) = 9.40/140 = .06714


c. 25(1) + 10(2) + 3(3) + 10(4) = 94/140 = .671


d. 25 + 10(2) + 3(3) + 10(3) = 84/140 = .600

Answer 1

Hello!

The answer is:

The correct answer is c.

$SluggingAverage=\frac{25(1)+10(2)+3(3)+10(40)}{140}=\frac{94bases}{140times}=0.671$

Why?

To calculate the slugging average or slugging percentage, we need to divide the number of total bases by the total times at bat.

$SluggingAverage=\frac{TotalBases}{TimesAtBat}$

We know that:

A single means 1 base.

A double means 2 bases.

A triple means 3 bases.

A homerun means 4 bases.

So, we know that:

$Singles=25=25bases\\Doubles=2*10=20bases\\Triples=3*3=9bases\\Homeruns=10*40=40bases\\TimesAtBat=140$

Then, substituting and calculating we have:

$SluggingAverage=\frac{25bases+20bases+9bases+40bases}{140}$

$SluggingAverage=\frac{94bases}{140times}=0.671$

Hence, the correct answer is c.

$SluggingAverage=\frac{25(1)+10(2)+3(3)+10(40)}{140}=\frac{94bases}{140times}=0.671$

Have a nice day!